Answer / vasundhara

int main()
{
int x=1;

if(*(char*)&x)
printf("little endian");
else
printf("big endian");

return 0;
}

Answer / anuraag

Vasudhara's solution is correct!
Still here is an alternative solution to check endianess
without using pointers...

int main()
{
int x=0x58;
char ch;
ch=x;

if(ch=0x58)
printf("Little Endian");
else
printf("Big Endian");
return 0;
}

Answer / udita

little indian

Answer / sudheer

little india

Answer / mohana

The below code snipeet tells whether the system is little
or big endian.

int main()
{
int x=1;

if(x)
printf("big endian");
else
printf("little endian");

return 0;
}

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