Answer / musa

swapping x and y using z as intermediary

memcpy(&z, &x, sizeof(x));
memcpy(&x, &y, sizeof(x));
memcpy(&y, &z, sizeof(x));

Answer / anish

Simple... use XOR (^) operator...
example suppose,
x=101 (binary)
y=010 (binary)
now,
Execute : x=x^y; -->> from LSB 1^0=1 0^1=1 1^0=1
now x=111
Execute : y=x^y; -->> from LSB 1^0=1 1^1=0 1^0=1
now y=101 (101 used to be the value of x)
Execute : x=x^y; -->> from LSB 1^1=0 1^0=1 1^1=0
now x=010 (010 used to be the values of y)

code snippet
{
x=10;
y=30;
//swap x and y
x=x^y;
y=x^y;
x=x^y;
}

now x=30 and y=10

any doubts please ask me....

Two's compliment of -5

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