How do you read arguments in a shell program - $1, $2 ..?
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Answer / madhavi
to read command line argments we hav to use echo $1
$2........whre $0-gives name of program,$#-gives number of
arguments passed and $* gives all the arguments.
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / seshadri sethi
Shell script accepts parameters in following format…
$1 would be the first command line argument, $2 the second,
and so on
$0 is the name of the script or function
If your script has more than 9 params then accept in
following way…
${12} : 12th param
${18} : 18th param
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / pitambar mishra
### Script for greater between 2 numbers
### name : greater_of_2_numbers.ksh
#! /bin/ksh
### If you won't supply 2 numbers then it will prompt you to 2 numbers. ###
if [ $# -ne 2 ] ($# : number of positional parameters)
then
echo "Usage: $0 <Enter 2 numbers>" ($0 : name of script)
exit 1
fi
### main script
if [ $1 -gt $2 ] ($1 and $2 : Two positional parameters)
then
echo "$1 is greater than $2"
elif [ $2 -gt $1 ]
then
echo "$2 is greater than $1"
else
echo "Two numbers are equal"
fi
To execute :
ksh greater_of_2_numbers.ksh 5 4
| Is This Answer Correct ? | 0 Yes | 0 No |
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