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show that among any group of five (not necessary consecutive
) integers, there are two with the same remainder when
divided by 4.
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Answer / lalala
generalized pigeon principle: If N objects are placed into k
boxes, then there is at least one box containing at least (ceiling) N/k objects.
let k = 4 ;
find N:
N/4 = 2 , N= 5, in order to get the answer 2..
| Is This Answer Correct ? | 17 Yes | 19 No |
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