Answer / v p p

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j=1,k,n,a[22][22],p,q,r,count=0;
clrscr();
A:
printf("Enter No. Of Rows Or Columns(Should Be Odd) : ");
scanf("%d",&n);
printf("\n");
if(n%2==0)
{
printf("Enter Odd No.s Only\n\n");
goto A;
}
k=(n+1)/2;
for(p=1;p<=n;p++)
{ for(q=1;q<=n;q++)
{
a[p][q]=NULL;
}
}
for(i=1;i<=(n*n);i++)
{
if(a[j][k]==NULL)
{
a[j][k]=i;
}
else
{
j=j+2;
k--;
if(j==n+2)
j=2;
if(k==0)
k=n;
if(j==0)
j=n;
if(k==n+1)
k=1;
a[j][k]=i;
}
j--;
k++;
if(j==0)
j=n;
if(k==n+1)
k=1;
}
for(p=1;p<=n;p++)
{
for(q=1;q<=n;q++)
{
r=a[p][q];
while(r>0)
{
r=r/10;
count++;
}
if(count==1)
printf(" 0%d",a[p][q]);
else
printf(" %d",a[p][q]);
if(q%n==0)
printf("\n\n");
count=0;
}
}
for(p=1;p<=n;p++)
{
for(q=1;q<=n;q++)
{
}
}
getch();
}

#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

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2 Answers   CNSI,

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