what is the output of the program?? #include<stdio.h> main ( ) {

what is the output of the program??

#include<stdio.h>

main ( )

{

int a=010,sum=0,tracker:

for(tracker=0;tracker<=a;tracker++)

sum+=tracker;

printf(“ %d\n”,sum);

}

what is the difference between a=10 and a=010??

Question Posted / ramana

3 Answers
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Oracle, I also Faced
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what is the output of the program?? #include<stdio.h> main ( ) { int a=010,sum=0,t..

Answer / vidyullatha

In linux:
Answer is 36 instead of 55.
i.e the loop iterates till tracker=8 instead of tracker=10.
Thats is because, I guess when u initialise a=010, compiler
takes a = octal 10 i.e in decimal it is 8.
So the loop iterates through tracker<=8.
This is my guess. I am not sure of the real answer.
Please let me know if any one knows the right answer.

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12 Yes

1 No

what is the output of the program?? #include<stdio.h> main ( ) { int a=010,sum=0,t..

Answer / xyz

near keyword int there is a colon so isnt tat a compling error

Is This Answer Correct ?

0 Yes

0 No

what is the output of the program?? #include<stdio.h> main ( ) { int a=010,sum=0,t..

Answer / manish

yes...
this is the case of memory mapping....

Is This Answer Correct ?

3 Yes

4 No

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