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what is the output of the program??
#include<stdio.h>
main ( )
{
int a=010,sum=0,tracker:
for(tracker=0;tracker<=a;tracker++)
sum+=tracker;
printf(“ %d\n”,sum);
}
what is the difference between a=10 and a=010??
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Answer / vidyullatha
In linux:
Answer is 36 instead of 55.
i.e the loop iterates till tracker=8 instead of tracker=10.
Thats is because, I guess when u initialise a=010, compiler
takes a = octal 10 i.e in decimal it is 8.
So the loop iterates through tracker<=8.
This is my guess. I am not sure of the real answer.
Please let me know if any one knows the right answer.
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / xyz
near keyword int there is a colon so isnt tat a compling error
| Is This Answer Correct ? | 0 Yes | 0 No |
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