Is there a datatype string in c++?How is the memory allocation?
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There is no DataType called String in C++.
String can be created using character array and delimited by
null character i.e. '/0'.
like char name[]={'n','i','t','h','i','n','
','d','e','v','a','n','g','0'}
or
char name={"nithin devang"}//it will automaticall append
null char.
Null character is having value (ASCII) Zero. (0 character
dont have ascii value 0)
--
If you still wish to use the keyword string you may declare
a macro
#define String char[];
my answer surety %=98%
-------------------
Read Expert C programming, The deep C secrets by Peter Van
Der Linden
| Is This Answer Correct ? | 2 Yes | 0 No |
There is no DataType called String in C++.
String can be created using character array and delimited by
null character i.e. '/0'.
like char name[]={'n','i','t','h','i','n','
','d','e','v','a','n','g','0'}
or
char name={"nithin devang"}//it will automaticall append
null char.
Null character is having value (ASCII) Zero. (0 character
dont have ascii value 0)
--
If you still wish to use the keyword string you may declare
a macro
#define String char[];
my answer surety %=98%
-------------------
Read Expert C programming, The deep C secrets by Peter Van
Der Linden
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ganesh chincholkar
Yes true string is not a datatype in C++ but it is implemented through Standard Template Library. And the string class has dynamic memory allocation.
eg:-
string str;
cin>>str;
string str gets dynamically allocated storage and that storage size is not permanent and can be modifies later.
after:
what happens behind screen is actualy:
string str = new char[strlen(str) + 1];
when you take input of the string str its size is calculated and you get the desired meomry.
| Is This Answer Correct ? | 0 Yes | 0 No |
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how can i access a direct (absolute, not the offset) memory address? here is what i tried: wrote a program that ask's for an address from the user, creates a FAR pointer to that adress and shows it. then the user can increment/decrement the value in that address by pressing p(inc+) and m(dec-). NOW, i compiled that program and opened it twice (in 2 different windows) and gave twice the same address to it. now look what happen - if i change the value in one "window" of the program, it DOES NOT change in the other! even if they point to the same address in the memory! here is the code snippet: //------------------------------------------------------ #include <stdio.h> //INCLUDE EVERY KNOWN HEADER FILE #include <conio.h> //FOR ANY CASE... #include <iostream.h> #include <dos.h> #include <process.h> main() { int far *ptr; //FAR POINTER!!! long address; char key=0; //A KEY FROM THE KEYBOARD int temp=0; clrscr(); cout<<"Enter Address:"; cin>>hex>>address; //GETS THE ADDRESS clrscr(); (long)ptr=address; temp=*ptr; //PUTS THE ADDRESS IN THE PTR cout<<"["<<hex<<(unsigned long)ptr<<"]="<<*ptr<<" = "<< (char)(*ptr); //SHOWS: [address]=value=ASCII symbol. while (key!=27) //WHILE YOU DONT PRESS ESC. { while(!kbhit()) //WHILE KEY IS NOT PRESSED { if (temp!=*ptr) { temp=*ptr; clrscr(); cout<<"["<<hex<< (unsigned long)ptr<<"]="<<*ptr<<" = "<<(char)(*ptr); }; //IF THE VALUE HAS CHANGED, CLEAR THE SCREEN AND SHOW //AGAIN if (key=='p') {key=0; (*ptr)++; } //INCREMENT VALUE if (key=='m') {key=0; (*ptr)--; } //DEC. VALUE }; key=getch(); //IF A KEY IS PRESSED, READ IT FROM THE //KEYBOARD }; return 0; //IF ESC WAS THE KEY, EXIT THE PROGRAM } //---------------------------------------------------------
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STL 
