write a program for 7*8 = 56 ? without using * multiply
operator ? output = 56
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Answer / guest
add 7 ,8 times & u 'll get the output
we can use while loop,or for loop
| Is This Answer Correct ? | 29 Yes | 2 No |
Answer / banavathvishnu
int main()
{
printf("%d",7<<3);
getch();
}
| Is This Answer Correct ? | 30 Yes | 7 No |
Answer / pavan_mustyala
Method1:
optimised code is to "left shift" the number 7 by 3 times.
Reason: 8 is (2 raised to power 3). So (7 * 8) is
equivalent to (((7*2)*2)*2). To multiply a number by 2,
shift it by 1 bit Left.
Method2:
Not optimised but it works. Addition in a loop.
int func()
{
int i;
int result = 0;
for(i = 0; i < 8; i++)
{
result = result + 7;
}
return result;
}
| Is This Answer Correct ? | 14 Yes | 4 No |
Answer / rama krishna sidhartha
Here is the logic.
void func()
{
int i;
int result = 0;
for(i = 0; i < 8; i++)
{
result = result + 7;
}
printf("%d",result);
}
| Is This Answer Correct ? | 8 Yes | 3 No |
Answer / manish soni bca 3rd year jaipu
#include<stdio.h>
#include<conio.h>
void main()
{
int i,ans;
ans=0;
for(i=0;i<8;i++)
ans=ans+7;
printf("%d",ans);
getch();
}
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / raju kalyadapu
int main()
{
int i=0,n=0;
while(i++<8)
n=n+7;
printf("7 * 8 is:%d",n);
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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