Answer / guest

add 7 ,8 times & u 'll get the output
we can use while loop,or for loop

Answer / banavathvishnu

int main()
{

printf("%d",7<<3);
getch();
}

Answer / pavan_mustyala

Method1:
optimised code is to "left shift" the number 7 by 3 times.

Reason: 8 is (2 raised to power 3). So (7 * 8) is
equivalent to (((7*2)*2)*2). To multiply a number by 2,
shift it by 1 bit Left.

Method2:
Not optimised but it works. Addition in a loop.

int func()
{
int i;
int result = 0;

for(i = 0; i < 8; i++)
{
result = result + 7;
}
return result;
}

Answer / rama krishna sidhartha

Here is the logic.
void func()
{
int i;
int result = 0;
for(i = 0; i < 8; i++)
{
result = result + 7;
}
printf("%d",result);
}

Answer / manish soni bca 3rd year jaipu

#include<stdio.h>
#include<conio.h>
void main()
{
int i,ans;
ans=0;
for(i=0;i<8;i++)
ans=ans+7;
printf("%d",ans);
getch();
}

Answer / raju kalyadapu

int main()
{
int i=0,n=0;
while(i++<8)
n=n+7;
printf("7 * 8 is:%d",n);
}

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