int main() { int i=1; switch(i) { case '1': printf("hello&q

int main()
{
int i=1;
switch(i)
{
case '1':
printf("hello");
break;
case 1:
printf("Hi");
break;
case 49:
printf("Good Morning");
break;
}
return 0;
}

Question Posted / srsabariselvan

3 Answers
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int main() { int i=1; switch(i) { case '1': printf("hello"); break; case..

Answer / srsabariselvan

The program Results in Error.
it will shows error "Duplicate case".
because '1' is equal to 49(ASCII of character 1).

Is This Answer Correct ?

8 Yes

0 No

int main() { int i=1; switch(i) { case '1': printf("hello"); break; case..

Answer / vishnu nayak

it will display Hi. In case '1', 1 is a character and it is
converted into ascii equivalent and then tested, which is
not equal to 1.

if the code is like this
swithc(i)
{
case 1:
printf("hi");
break;
case 1:
printf("Hello ");
break;

} then it will surly give compilation error.

Is This Answer Correct ?

4 Yes

2 No

int main() { int i=1; switch(i) { case '1': printf("hello"); break; case..

Answer / hussain reddy

error because duplicate case values

Is This Answer Correct ?

1 Yes

1 No

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