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You have an array of n integers, randomly ordered with value 1
to n-1.The array is such that there is only one and one value
occurred twice. How will you find this number?
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Answer / balaji ganesh
#include<stdio.h>
void main()
{
int a[100],n,i,j;
clrscr();
scanf("%d",&n,printf("enter size of array:"));
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
if(a[i]==a[j])
{
printf("second occurence value: %d",a[i]);
break;
}
getch();
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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