How to define variable 9(20) in COBOL, because compiler does not allow us to d

How to define variable 9(20) in COBOL, because compiler
does not allow us to declare variables with Pic 9(18). Can
anyone please let me know the answer... I know one answer
to this question which is to use Compiler option Arith
(Extend) during Compilation. It extends the maximum limit
to 9(32)..Just wanted to know if there is any other way to
extend this?

Question Posted / mainframe_professional

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How to define variable 9(20) in COBOL, because compiler does not allow us to declare variables wit..

Answer / abc

try with this:

01 VARIABLE-ABC.
03 VAR-1 PIC 9(18).
03 VAR-2 PIC 9(2).

This may work, please try and see.

Is This Answer Correct ?

10 Yes

1 No

How to define variable 9(20) in COBOL, because compiler does not allow us to declare variables wit..

Answer / vikram

01 VAR-1 PIC 9(18).
change the datatype then it's possible

01 VAR-1 PIC x(20).

Is This Answer Correct ?

1 Yes

0 No

How to define variable 9(20) in COBOL, because compiler does not allow us to declare variables wit..

Answer / dimpy19

try with this:

01 VARIABLE-ABC.
03 VAR-1 PIC 9(18).
03 VAR-2 PIC 9(2).

or
use PROCESS ARITH(EXTEND) before IDENTIFICATION DIVISION

ARITH option syntax

.-COMPAT-.
>>-ARITH(-+-EXTEND-+-)-----------------------------------------><

When you specify ARITH(EXTEND):
The maximum number of digit positions that you can specify in the PICTURE clause for packed-decimal, external-decimal, and numeric-edited data items is raised from 18 to 31.

Is This Answer Correct ?

0 Yes

0 No

How to define variable 9(20) in COBOL, because compiler does not allow us to declare variables wit..

Answer / sachin borase

Use the varchar.

01 var-char-variable.

49 ws-letch s9(4) comp.
49 ws-text 9(20).

Is This Answer Correct ?

2 Yes

9 No

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