Answer / shanu zabeen

//consider the follwing program part

for(int k = 0; k < 10; k++);
System.out.println("hi");
int k = 9
while(k < 10)
{
System.out.println("world");
k++;
}
//now lets trace the program as follows
start, at the for loop, k is initialized to 0 with a scope
local to the for loop itself.
k = 0
Is it less than 10? yup, so we enter the loop.
Next, we have output,
hi.
Since there is no brackets, the for loop applies only to the
very next line. In this case, the output. So, return to the
top of the loop, k increments by 1
k = 1
and we proceed again since 1 < 10.
The output "hi" is printed again.
Go back to the top of the loop, increment k, and recheck the
loop condition of k < 10. The above cycle repeats until k is
incremented and equals 10. Since 10 is not less than 10,
exit the for loop.
:
k = 10
next
Now, declare an integer k to be equal to 9.
k = 9
Note it has local scope to this part of the program but,
since the for for loop previous one is gone from memory, so
too is the integer k that it (the loop) declared.
Thus, there is no conflict. So, an integer variable k (one
different from the last) is now = 9

Check the while boolean condition and k is less than 10 so
enter the while loop.
Next, print the output
"world"
Next, increment k by 1 ("k++") so
k = 10
Check the while loop conditional again but, this time, it's
false. k is not less than 10 anymore. So, exit the while loop.

1+(2*3)+(4*5*6)+(7*8*9*10)+... specified input value

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