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main()
{
int i=0;
while(+(+i--)!=0)
i-=i++;
printf("%d",i);
}
- 4 Answers
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Answer / furquan
Here what happens is :
while(+(+i--)!=0)
i = 0
so 0 != 0 is false hence condition for while fails. Now
there is also a post decrement operator. So value of i turns
out to be -1. and that is which is printed.
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / rameshp
ans s -1
Bec
while(1!=0) this s false..so next line don't exec..
so i-- means 0--= -1
finally we get -1
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / priyadarshan kasta
-1.
i don't know why.
plz post the reason
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / rayan
ans is -1.
Initially i == 0, when it enters into while loop
while(+(+i--)!0)
in 1st iteration i value ll be 0 only due to post decrement
operator.
in second iteration as i gets its post decremented value n
becomes -1 & -1 ~= 0 condition gets true & while loop breaks.
here + operator in the loop is doing ntg.
| Is This Answer Correct ? | 2 Yes | 1 No |
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