pierrot's divisor program using c or c++ code
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Just came across this question, felt worth sharing, so here it is I want you to make a C/C++ program that for any positive integer n will print all the positive integers from 1 up to it and then back again! Let's say n=5 I want the program to print: 1 2 3 4 5 4 3 2 1. Too easy you say? Okay then... You can ONLY USE: 1 for loop 1 printf/cout statement 2 integers( i and n) and as many operations you want. NO if statements, NO ternary operators, NO tables, NO pointers, NO functions!
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Badboy is defined who has ALL the following properties: Does not have a girlfriend and is not married. He is not more than 23 years old. The middle name should be "Singh" The last name should have more than 4 characters. The character 'a' should appear in the last name at least two times. The name of one of his brothers should be "Ram" Write a method: boolean isBadBoy(boolean hasGirlFriend , boolean isMarried, int age , String middleName , String lastName , String[] brotherName); isHaveGirlFriend is true if the person has a girlfriend isMarried is true if the person is married age is the age of the person middleName is the middle name of the person lastName is the last name of the person brotherName is the array of the names of his brothers
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C 
