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class test
{
private static void main(String []adsf)
{
}
}
explain me that the above code is error or exception
- 3 Answers
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Answer / bhargava
Code will throw exception. Because usually every stand
alone program execution should start with main method. It
should be public other wise this method doesnt exposed to
out side to run.
| Is This Answer Correct ? | 12 Yes | 0 No |
Answer / sri
It will not generate any compile time error, but while
running the program it will generate the output as "main
method is not public".....
| Is This Answer Correct ? | 7 Yes | 0 No |
Answer / xavier
This will throw a runtime error stating main method not public
This is because main method is the starting point of program
execution and it should be accessible by JVM
| Is This Answer Correct ? | 2 Yes | 0 No |
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