Answer / prashant

Sir, i am not able to answer of this program. please send
to me answer of this program.

Answer / shameer.k.g

i have seen above this big codeing is not needed because it
is simple program,it need only very less codeing, i have no
time to write ,i have studied this program in
btech,tommorow i have written test for dell

Answer / vadivel t

In the code above, which i have answered has unwanted
assignment to No ie ., no = 999, and i, j and all pls
neglect those parameters.. just i hav written in hurry...
Dont mind

Answer / vikas

Can any one help me with this please, I cant get it right. I
have a test on 23/05/2011... Thanks

1
1 2
1 2 3
1 2 3 4

Answer / vadivel t

Hi,

I have written code for only 3 digit numbers(u may not get
exact result for 100, 200, 113 etc ). This is just for an
idea from which u can build ur logic.
I accept... This code can be optimised.

Dont think that code is too lengthy... cos we hav to hav
limited if, else if or switch for this requirement.

Apply ur logic for 123455677 kind of nos.

#include <stdio.h>
/*Convert no to word... only for 3 digit nos*/
void ConvertToWord(int length);
char* Tens(int *a);
int Temp[10], Length = 0;

int main()
{
int No = 999, DupNo, i, j;
printf("ENTER THE THREE DIGIT NO: ");
scanf("%d", &No);
DupNo = No;
while(DupNo != 0)
{
Temp[Length] = DupNo % 10;
DupNo = DupNo / 10;
Length++;
}
printf("%d - ", No);
ConvertToWord(Length);
_getch();
}


void ConvertToWord(int Length)
{
while(Length != 0)
{
switch(Length)
{
case 0:
break;
case 1:
switch(Temp[Length - 1])
{
case 0:
break;
case 1:
printf("ONE ");
break;
case 2:
printf("TWO ");
break;
case 3:
printf("THREE ");
break;
case 4:
printf("FOUR ");
break;
case 5:
printf("FIVE ");
break;
case 6:
printf("SIX ");
break;
case 7:
printf("SEVEN ");
break;
case 8:
printf("EIGHT ");
break;
case 9:
printf("NINE ");
break;
}
Length--;
break;

case 2:
switch(Temp[Length -1])
{
case 0:
break;
case 1:
break;
case 2:
printf("TWENTY ");
break;
case 3:
printf("THIRTY ");
break;
case 4:
printf("FORTY ");
break;
case 5:
printf("FIFTY ");
break;
case 6:
printf("SIXTY ");
break;
case 7:
printf("SEVENTY ");
break;
case 8:
printf("EIGHTY ");
break;
case 9:
printf("NINETY ");
break;
}
Length--;
break;

case 3:
printf("%s HUNDRED AND ", Tens(&Temp[--
Length]));
break;
}
}

}

char* Tens(int *a)
{
char *ch;
switch(*a)
{
case 0:
ch = "ZERO";
break;
case 1:
ch = "ONE";
break;
case 2:
ch = "TWO";
break;
case 3:
ch = "THREE";
break;
case 4:
ch = "FOUR";
break;
case 5:
ch = "FIVE";
break;
case 6:
ch = "SIX";
break;
case 7:
ch = "SEVEN";
break;
case 8:
ch = "EIGHT";
break;
case 9:
ch = "NINE";
break;
}
return ch;
}

How do we swap or interchange any 2 numbers without using Temporary variable...Anybody can pls answer it.. Thanks in Advance

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