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11. static class A {
12. void process() throws Exception { throw new Exception();
}
13. }
14. static class B extends A {
15. void process() { System.out.println(”B”); }
16. }
17. public static void main(String[] args) {
18. new B().process();
19. }
What is the result?
1 B
2 The code runs with no output.
3 Compilation fails because of an error in
line 12.
4 Compilation fails because of an error in
line 15.
- 6 Answers
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Answer / r.jainrocks@gmail.com
Compilation fails
static keyword not allowed here
at line 11 and 14
| Is This Answer Correct ? | 9 Yes | 3 No |
Answer / vasanth g
Here we are directly process method of class b.
so ans B that is 1st option....
consider this
static classA {
void process() throws Exception { throw new Exception(); }
}
static class B extends A {
void process() { System.out.println(�B �); }
}
public static void main(String[] args) {
A a=new B();
a.process();
}
in this program compilation fails at a.process
because compiler doen't know that reference a point on class
B where there's no exception. a is of A type and A's method
throws exception that isn't handled .a.process() enclosed in
try catch block.
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / manikandan [ gtec,vellore ]
Answer is 1)B because we directly calling a process method
in class B
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / bhanu
hi,
Keep the whole code in a class
Ex:
class Sample
{
.....
..... //the above code
.....
.....
}
Now it will not give any error while compilation.
It is the concept of static nested classed
Thank you
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / souvik
The answer will be first option B since the object created is of B type and it is calling directly the process method in B class
| Is This Answer Correct ? | 0 Yes | 0 No |
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