how to display 2-D array elements in spiral
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Answer / om
#include<iostream>
using namespace std;
//----------------------
void spiral_way(int Row_size,int Column_size,int a[][4])
{
int
i,j,d=0,Current_row_size=Row_size,Current_column_size=Column_size,
Counter=Row_size*Column_size;
while(Counter>0) //Initailly my "Counter" is set to
total no. of elemnet in my 2-D array. so now I will
decrement it as I cover a element.
{
i=d;j=d;
while(j<Current_column_size-1) {
printf("%d\t",a[i][j]); j++; Counter--;}
//this is for printing the first row in forward direction.
while(i<Current_row_size-1) {
printf("%d\t",a[i][j]); i++; Counter--;}
//this is for printing the last cloumn in downward direction.
while(j>d) {
printf("%d\t",a[i][j]); j--; Counter--; }
//this is for printing the last row in backward direction.
while(i>d) {
printf("%d\t",a[i][j]); i--; Counter--; }
//this is for printing the first column in upward direction.
//When I completed the outer rectangle I move in to inner
rectangle by incrementing "d".
//and decrementing the "Current_row_size" and
"Current_column_size".
d++;
Current_row_size--;
Current_column_size--;
}
}
//-------------------------
int main()
{
int a[5][4]={{1,2,3,4},
{5,6,7,8},
{9,10,11,12},
{13,14,15,16},
{17,18,19,20}
};
spiral_way(5,4,a);
//system("pause");
return 0;
}
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / raj
#define subscript 5
void spiral()
{
int a[subscript][subscript],i,j,k,l,m,p,q;
p=q=subscript ;
for(i=0;i<p;i++,p--)
{
for(j=i;j<n-1;j++)
printf("%d",a[i][j]);
for(k=i;k<j;k++)
printf("%d",a[k][j]);
for(l=k;l>i;l--)
printf("%d",a[l][k]);
for(m=k;m>i;m--)
printf("%d",a[i][m]);
}
if(q%2!=0)
printf("%d",a[j][j]);
}
| Is This Answer Correct ? | 2 Yes | 1 No |
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