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ERRORS Interview Questions
Questions Answers Views Company eMail

ORA-27074: unable to determine limit for open files

1 2767

ORA-27075: SSTMOFRC constant too large

1 2931

ORA-27076: unable to set limit for open files

1 3099

ORA-27077: too many files open

1 8097

ORA-27078: unable to determine limit for open files

1 10611

ORA-27080: too many files open

1 3096

ORA-27081: unable to close the file

1 2987

ORA-27083: waiting for async I/Os failed

1 7770

ORA-27084: unable to get/set file status flags

1 2930

ORA-27086: unable to lock file - already in use

1 7444

ORA-27087: unable to get share lock - file not readable

1 2783

ORA-27088: unable to get file status

1 3313

ORA-27089: unable to release advisory lock

1 2908

ORA-27091: unable to queue I/O

1 7473

ORA-27092: size of file exceeds file size limit of the process

1 6146


Un-Answered Questions { ERRORS }

How will you Handle Error in SQL SERVER 2008?

2415


when i open the system error dialog box come memory could not be read some.

2506


2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]

2896


if the lengths of two wires are same and the area of cross sections is 4:7 then what will be the ratio of current passing through these wires

2719


For pH-4 calculation it is subtracted from the previous pH7 buffer value is the same procedure to be followed for calculation of remaining buffers??

1639


What is the meaning of lock escalation and why/how to stop this?

2670


IMP-00000: Import terminated unsuccessfully Hi all . when i go to restore oracle dmp file in my database ans typing this command , C:UsersW>imp HR2011/HR2011@XE TABLES=* dmpfile=F:Share223.27.244.72EXP 2017-0113030008FU160710ZIP/FU160710.DMP this message was showed to me and restore mission filed . LRM-00101: unknown parameter name 'dmpfile' IMP-00022: failed to process parameters, type 'IMP HELP=Y' for help IMP-00000: Import terminated unsuccessfully how i can fix this problem plzzz

2939


what are the test cases for ticket vending machine?

4298


ORA-26076: cannot set or reset value after direct path structure is allocated

1979


Jetking is C C

2683


ORA-26032: index string.string loading aborted after string keys

2118


What is the difference between return code and completion code. When i was searching in the direct for the problem, the following errors displayed. Please can any1 explain these. Completion Code => 4 Message Id => XXDR012I Short Text => XDR field overflow. Key=SER. Len=8. Completion Code => 8 Message Id => XSQF009I Short Text => Sys call open() failed.Filename=/opt/apps/cdt3/USA/outbound/CD810O.errno=17. Completion Code => 8 Message Id => XCPR010I Short Text => Open failed for copy in OPEN_DEST_DATA. Errno=17. can you explain those 3 completion codes and also with difference between return code and completion code

11885


What is SCD (Slowly Changing Dimensions)? What are its types?

2682


When do you get "getwmicomexception"?

2692


//jobname positional parms,keyword parms,.... Restart=step3 //.. //.. //.. //step3 exec=xxxx //... //step4 exec=yyyy,cond=(0,Le,step3) //.. //step5 exec=zzzz Restart =step 3 executes step3.Step 3 gives some return code.In step 4,the test is passed as 0 is less than step 3.So step 4 is bypassed and is not executed. and the program is responsible for issuing the return code that was not even loaded in the main storage. The result: no return code can exist In the steps that follow any test of COND parameter tat attempts to interrogate this non-existent return code will be ignored . Step 5 will be e executed. IN THIS EXAMPLE WHAT DOES XXXX YYYY ZZZZ MEAN?? PLEASE CAN ANYONE SAY...

2865