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main() { char *p1="Name"; char *p2; p2=(char *)malloc(20); while(*p2++=*p1++); printf("%s\n",p2); } what is the output?
7 27136The whole thing moves/ (B) around the concept of building a small dynamic/(C) organisation into a larger one./(D) No error.
3 28165Post New AMCAT Interview Questions
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In a barber shop there are 2 doors. customer come in 1 door, leave in other. minimum # of chairs. barber spend his life in cutting. always barber can cut 1 customer. few chairs in the shop. if barber busy customer waits, if chairs full, customer leave. if no customer, barber sleeps. treat barber and customer as 2 threads. you can use Semaphore class with arrive and depart and count as parameter.
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