Who are investment bankers?

1184

How to implement dynamic select and smart prompt? What's the major difference between them?

579

Explain me the bootstrap basic table?

3

Elaborate the term WebService and how it differ from Remoting?

954

After first installation of Solaris 10, what and all the Securities We need to set and how ?

2276

How can you relate the goals you have for yourself to the goals of Aeropostale?

1229

how to find 5 kilo meter long under ground 33 kv cable fault location if IR VALUE shows 0.05 M ohm @5000 volt.and cable fault locator shows some time fault distance 3 kilo meter ,3.7 kilo meter and some time 1 kilo meter? now how to find the fault location that where is leakage. note--it is tested with 5000 kv megger and insulation resistance is 0.05 M ohm. and some time 0.03 M ohm comes.

2215

What are the similarities and difference between class and structure in .net?

1022

How do you change a file type in windows 10?

823

How to convert a list into other data types ?

484

What are the features of dbms?

946

What are the new enhancements done in default project template of asp.net mvc 4?

1045

Explain quick sort?

966

How to use Apache Zookeeper command line interface?

1138

We have drive feeding an output contactor for a 5000 hp motor @ 5kV application. The motor FLA is 629amps x 1.25% service factor = 786.25 amps The cable that we current have in place between the drive and the output contactor is 350kcmil- MV-105 (parallel cables). Per the NEC table 310.60 (C) (69). This show the cable ampacity is at 615 amps per cable for a rating of 1230 amps. We have derated the cable for the cable tray and the multiple cables application and our calculations show that after the correction factor factor we are at 922amps. 1230 amps x .75% correction factor factor = 922.5 amps. The customer is driving us to then use another safety factor of .25% off of the already derated cable. Can you please provide a longhand calculation for your solution on this application?

2150