Answer / susie

Answer :

H

Explanation:

* is a dereference operator & is a reference operator. They
can be applied any number of times provided it is
meaningful. Here p points to the first character in the
string "Hello". *p dereferences it and so its value is H.
Again & references it to an address and * dereferences it
to the value H.

Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2) without making use of any floating point computations at all.

2 Answers   Mentor Graphics, Microsoft,

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#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }

1 Answers  

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void main() { int x,y=2,z; z=(z*=2)+(x=y=z); printf("%d",z); }

4 Answers  

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#define max 5 #define int arr1[max] main() { typedef char arr2[max]; arr1 list={0,1,2,3,4}; arr2 name="name"; printf("%d %s",list[0],name); }

1 Answers  

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what is the output of the below program & why ? #include<stdio.h> void main() { int a=10,b=20,c=30; printf("%d",scanf("%d%d%d",&a,&b,&c)); }

6 Answers   CSC, IIIT,

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What is the match merge ? compare data step match merge with proc sql merge - how many types are there ? data step vs proc sql

0 Answers  

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int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().

1 Answers  

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main() { printf("%x",-1<<4); }

3 Answers   HCL, Sokrati, Zoho,

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main( ) { static int a[ ] = {0,1,2,3,4}; int *p[ ] = {a,a+1,a+2,a+3,a+4}; int **ptr = p; ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *++ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); ++*ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); }

2 Answers   Persistent,

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int a = 10 + 10 .... ,... A = A * A What would be the value of A? The answer is 120!! Could anyone explain this to me.

2 Answers   Bosch, eInfochips, HCL, IHCL,

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main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  

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what is the output of following program ? void main() { int i=5; printf("%d %d %d %d %d ",i++,i--,++i,--i,i); }

10 Answers  

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