Answer / siva kumar

for example :
Here a is three(3).

calling fun(3) in main function.
FUN(3) {
calling fun(2) {
calling fun(1) {
calling fun(0) {
N>0 found.
}
printed 0
calling second fun(-1) {
N>0 found.
}
}
printed 1
calling second fun(0) {
N>0 found.
}
}
printed 2
calling second fun(1) {
calling fun(0) {
N>0 found.
}
printed 0
calling second fun(-1) {
N>0 found.
}
}
}

int i; main(){ int t; for ( t=4;scanf("%d",&i)-t;printf("%d\n",i)) printf("%d--",t--); } // If the inputs are 0,1,2,3 find the o/p

2 Answers  

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main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }

1 Answers  

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int aaa() {printf(“Hi”);} int bbb(){printf(“hello”);} iny ccc(){printf(“bye”);} main() { int ( * ptr[3]) (); ptr[0] = aaa; ptr[1] = bbb; ptr[2] =ccc; ptr[2](); }

1 Answers  

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main() { int i=-1; +i; printf("i = %d, +i = %d \n",i,+i); }

1 Answers  

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main() { int y; scanf("%d",&y); // input given is 2000 if( (y%4==0 && y%100 != 0) || y%100 == 0 ) printf("%d is a leap year"); else printf("%d is not a leap year"); }

1 Answers  

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Write a program using one dimensional array to assign values and then display it on the screen. Use the formula a[i]=i*10 to assign value to an element.

1 Answers   Samar State University,

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#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

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Is the following code legal? typedef struct a aType; struct a { int x; aType *b; };

1 Answers  

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main() { int i; clrscr(); for(i=0;i<5;i++) { printf("%d\n", 1L << i); } } a. 5, 4, 3, 2, 1 b. 0, 1, 2, 3, 4 c. 0, 1, 2, 4, 8 d. 1, 2, 4, 8, 16

4 Answers   HCL,

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main() { float f=5,g=10; enum{i=10,j=20,k=50}; printf("%d\n",++k); printf("%f\n",f<<2); printf("%lf\n",f%g); printf("%lf\n",fmod(f,g)); }

1 Answers  

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,

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main() { char *cptr,c; void *vptr,v; c=10; v=0; cptr=&c; vptr=&v; printf("%c%v",c,v); }

1 Answers  

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