Answer / guest

a)

Answer / govind verma

OK I am done. reason bollean expression in if evaluate in such manner first (1||0) will execute and first expresiion of this boolean expression is one so control will not goes to chek any thing i.e whole expression evaluate as (1||0)as 1(true) now expression becom like dis if(1&&(0||1))
now (0||1) expressiion will evaluate in this expression value of left hand side of || operator is 0(false) so control goes to check further and right hand side it recieve 1 then the value of wholl expression becom 1 thn nw orignal expression looks like if(1&&1)
nw (1&&1) is evalute in this case control check both the value of the operator(&&) is one then this return 1 otherwise return 0 then orignal expression like this if(1)
1 is nonzero value this mean condition is true then code of if block will be execute which is OK I am done.

Answer / naveen kumar

ok i am gone...because in this case the condition if((1||0)
&&(0||1)
always remain true. hence the answer is ok i am done...i.e.
(a

Answer / priti soni

d

Answer / karthi

c.compile error

posted by surbhi just now main() { float a = 5.375; char *p; int i; p=(char*)&a; for(i=0;i<=3;i++) printf("%02x",(unsigned char) p[i]); } how is the output of this program is :: 0000ac40 please let me know y this output has come

2 Answers   GATE,

main() { int i = 0xff ; printf("\n%d", i<<2); } a. 4 b. 512 c. 1020 d. 1024

2 Answers   HCL,

main() { static int var = 5; printf("%d ",var--); if(var) main(); }

1 Answers  

main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

main() { char *p = “ayqm”; char c; c = ++*p++; printf(“%c”,c); }

1 Answers  

Write, efficient code for extracting unique elements from a sorted list of array. e.g. (1, 1, 3, 3, 3, 5, 5, 5, 9, 9, 9, 9) -> (1, 3, 5, 9).

13 Answers   Intel, Microsoft, TCS,

which function is used to clear the buffer stream on gcc? for example: I wrote following code on gcc #include<stdio.h> int main(void) { char ch; int a,b; printf("\nenter two numbers:\t"); scanf("%d%d",&a,&b); printf("enter number is %d and %d",a,b); printf("\nentercharacter:\t"); scanf("%c",&ch); printf("enter character is %c",ch); return 0; } in above progarm ch could not be scan. why?plz tell me solution.

2 Answers  

Derive expression for converting RGB color parameters to HSV values

1 Answers  

main() { main(); }

1 Answers  

const int perplexed = 2; #define perplexed 3 main() { #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed); } a. 0 b. 2 c. 4 d. none of the above

1 Answers   emc2, HCL,

source code for delete data in array for c

1 Answers   TCS,

struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,