How many bytes will be allocated for the following record
description
entries?
01 REC-A.
05 A PIC S9(4).
05 B PIC XXXBXXX.
05 C PIC ____9.99.
05 D PIC S9(5) COMP-3.
05 E PIC 9(3) COMP.
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Answer / khamuruddin
05 A PIC S9(4). = 4
05 B PIC XXXBXXX. = 7
05 C PIC ____9.99. = 4
05 D PIC S9(5) COMP-3. = 3
05 E PIC 9(3) COMP. = 2
-------
20
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| Is This Answer Correct ? | 23 Yes | 2 No |
Answer / ezhil_18
@ above
COMP3 data require always requrie n+1/2 bytes. here 5+1/2
takes only 3 bytes not 4 bytes.
| Is This Answer Correct ? | 14 Yes | 1 No |
Answer / raj
05 A PIC S9(4) -> 4
05 B PIC XXXBXXX -> 7
05 C PIC ____9.99 -> 4
05 D PIC S9(5) COMP-3 -> 3
05 E PIC 9(3) COMP -> 2
SO TOTAL OF 20 BYTES
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / vijay
05 A PIC S9(4) -> 5 (BY CONSIDERING ONE SIGN BIT)
05 B PIC XXXBXXX -> 7 ( AS YOU ALL KNOWS ABOUT THIS)
05 C PIC ____9.99 -> 4 (SPACE AND 9V99=9(3))I THINK
05 D PIC S9(5) COMP-3 -> 3 ((5/2)+0.5)FOR ODD NUM WE HAVE
CONSIDER ONE 1/2 BYTE ONLY=0.5)
05 E PIC 9(3) COMP -> 2 (9(1) TO 9(4)=HALFWORD=2BYTES)
(9(5) TO 9(9)= WORD= 4 BYTES)
(9(10) TO 9(18)= FULLWORD=8BYTES)
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / suresh kumar
sorry to post the last answer, I would like to go for 24
bytes.
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / guest
y there is soo much confusion.. plz mention correct ans..
else it will confuse the readers.. :(
| Is This Answer Correct ? | 3 Yes | 4 No |
Answer / priyanka
I think t will be 25 since
05 A PIC S9(4). - 5 :4 + 1 sign byte
05 B PIC XXXBXXX. - 7
05 C PIC ____9.99. - 8
05 D PIC S9(5) COMP-3. - 3
05 E PIC 9(3) COMP. - 2
__________________________________________
Total = 25 bytes
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / raj
05 A PIC S9(4) -> 4
05 B PIC XXXBXXX -> 7
05 C PIC ____9.99 -> 4
05 D PIC S9(5) COMP-3 -> 4
05 E PIC 9(3) COMP -> 2
SO TOTAL OF 21 BYTES
| Is This Answer Correct ? | 0 Yes | 4 No |
What is the difference between PIC 9.99 and 9v99 in COBOL?
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