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01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING".
01 NAME2 PIC X(13).
now I want to display the value of NAME1 in reverse order
i.e value should be displayed as "GNIMMARGORP LOBOC"
HOW can I do that ??? please let me know if any one knows
it.

Answers were Sorted based on User's Feedback



01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / mr2981

to reverse the string use REVERSE function

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING".
01 NAME2 PIC X(13).

MOVE FUNCTION REVERSE(NAME1) TO NAME2.

Is This Answer Correct ?    34 Yes 3 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / elizabeth

Using reference modification each character can be
extracted and placed in the next string in any order

Is This Answer Correct ?    11 Yes 0 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / rajani

working-storage section.
01 name1 pic x(17) value 'cobol programming'.
01 name2 pic x(17).
01 i pic 99.
01 j pic 99 value 1.
procedure division.
perform para varying i from 17 by -1 until i<1.
display name2.
stop run
para.
move name1(i:1) to name2(j:1).
add 1 to j.

Is This Answer Correct ?    11 Yes 1 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / jagan

This should convert the string in reverse order without any
built-in functions . And one more thing is COBOL PROGRAMMING
is actually 17 characters.

DATA DIVISION.
WORKING-STORAGE SECTION.
01 NAME-1 PIC X(17) 'COBOL PROGRAMMING'
01 NAME-2
05 NAME-21 PIC X(1) OCCURS 17 TIMES.

01 I PIC X(2)
01 J PIC X(2)


PROCEDURE DIVISON.
MAIN-PARA.
MOVE 0 TO J.
PERFORM READ-NAME VARYING I FROM 17 BY -1 UNTIL I > 0.
STOP RUN.


READ-NAME
ADD 1 TO J.
MOVE NAME-1(I) TO NAME-21(J).
END-READ-NAME.

Correct me in case any problem with above code.

Is This Answer Correct ?    7 Yes 4 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / sairanga

procedure division.
move name1(17:1) to name2(1:1).
move name1(16:1) to name2(2:1).
move name1(15:1) to name2(3:1).
.
.
.

move name1(2:1) to name2(16:1).
move name1(1:1) to name2(17:1).
display name2.
stop run.

Is This Answer Correct ?    3 Yes 1 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / sunil

Hi,

Please try this code it should work.

IDENTIFICATION DIVISION.
PROGRAM-ID. MID.
ENVIRONMENT DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 STR1 PIC X(17) VALUE IS 'COBOL PROGRAMMING'.
01 STR2 PIC X(1).
01 STR3 PIC X(17) VALUE SPACE.
01 STRLEN PIC 9(2).

PROCEDURE DIVISION.
INSPECT STR1 TALLYING STRLEN FOR CHARACTERS.
DISPLAY STRLEN.
PERFORM UNTIL STRLEN < 1

MOVE STR1(STRLEN:1) TO STR2
DISPLAY STR2
STRING
STR3 DELIMITED BY SPACE
STR2 DELIMITED BY SPACE
INTO STR3
COMPUTE STRLEN STRLEN - 1
DISPLAY STR3
END-PERFORM.
DISPLAY STR3.
STOP RUN.


Thanks,
Sunil

Is This Answer Correct ?    0 Yes 0 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / ankur kar

In order to reverse the String the only way is by declaring
the string as an array and then sequentially arrage the
array based on the asending/desending order of the array
and then display the sequential result accordingly.
Otherwise there is no command in COBOL that will allow the
string to be displayed in the reverse order.

Is This Answer Correct ?    3 Yes 4 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / devraj pradhan

as per my knowledge this problem can be solve by STRING AND
UNSTRING COMMAND as in that there is REPLACING option is
there by which any string can be replace in reverse order

Is This Answer Correct ?    0 Yes 4 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / satya

As per my knowledge we can solve this problem with use of
STRING AND UNSTRING commands,first UNSTRING the give string
and add all the characters according to our choice by using
STRING COMMAND.

Is This Answer Correct ?    1 Yes 6 No

01 NAME1 PIC X(13) VALUE "COBOL PROGRAMMING". 01 NAME2 PIC X(13). now I want to ..

Answer / rajul

just define
01 name2 picX(13) right justified.

and then use move stmt
move name1 to name2.

Is This Answer Correct ?    2 Yes 13 No

Post New Answer

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IDENTIFICATION DIVISION. PROGRAM-ID. UPDT. AUTHOR.anbu. DATE-WRITTEN. AUG 13. ENVIRONMENT DIVISION. INPUT-OUTPUT SECTION. FILE-CONTROL. SELECT CMSTR ASSIGN TO CINP1 ORGANIZATION IS INDEXED ACCESS IS SEQUENTIAL RECORD KEY CM2-KEY FILE STATUS IS WS-CMSTR-FST. SELECT CTAB ASSIGN TO CINP2 ORGANIZATION IS ACCESS IS SEQUENTIAL RECORD KEY VSAM-WHSE- KEY FILE STATUS IS WS-CTAB- FST. DATA DIVISION. FILE SECTION. FD CMSTR. COPY RXCYFC20. FD CTAB. COPY AITYWHSE. ************************************************************ ****** *** WORKING STORAGE VARIABLES *** ************************************************************ ****** WORKING-STORAGE SECTION. 01 WS- VARIABLES. 05 WS-EB PIC X(02) VALUE ZEROES. 05 WS-DIV PIC 9(03) VALUE ZEROES. 05 WS-CMF-RECS-REWRITTEN PIC 9(01) VALUE ZERO. *** FILE STATUS VARIABLES *** 05 WS- FILESTATUS. 10 WS-CMSTR-FST PIC 9(02) VALUE ZEROES. 10 WS-CTAB-FST PIC 9(02) VALUE ZEROES. *** END OF FILE VARIABLES *** 05 WS-CMSTR-EOF PIC X(01) VALUE 'N'. 88 WS-CMSTR-EOF-YES VALUE 'Y'. 88 WS-CMSTR-EOF-NO VALUE 'N'. 05 WS-CTAB-EOF PIC X(01) VALUE 'N'. 88 WS-CTAB-EOF-YES VALUE 'Y'. 88 WS-CTAB-EOF-NO VALUE 'N'. **** ERROR VARIABLES **** 05 WC-ABEND-900 PIC 9(03) VALUE 900. 05 WE-ERR-CODE PIC 9(02) VALUE ZEROES. 05 WE-ABEND-CODE PIC 9(03) VALUE ZEROES. ************************************************************ **** ********* PROCEDURE DIVISON ********** ************************************************************ **** PROCEDURE DIVISION. 0000- BEGIN. PERFORM 1000-INITIALISE THRU 1000- EXIT. PERFORM 2000-PROCESS THRU 2000- EXIT UNTIL WS-CMSTR-EOF- YES. DISPLAY 'WS-CMF-RECS-REWRITTEN :' WS-CMF-RECS- REWRITTEN. PERFORM 5000-CLOSE THRU 5000- EXIT. GOBACK. 0000- EXIT. EXIT. 1000- INITIALISE. OPEN I-O CMSTR. EVALUATE WS-CMSTR- FST WHEN 00 WHEN 97 CONTINUE WHEN OTHER DISPLAY 'ERROR IN READING INPUT FILE: ' DISPLAY WS-CMSTR-FST MOVE WS-CMSTR-FST TO WE-ERR-CODE PERFORM 9999-ABEND-PARA THRU 9999-EXIT END-EVALUATE. OPEN INPUT CTAB. EVALUATE WS-CTAB-FST WHEN 00 WHEN 97 CONTINUE WHEN OTHER DISPLAY 'ERROR IN READING INPUT FILE: ' DISPLAY WS-CTAB-FST MOVE WS-CTAB-FST TO WE-ERR-CODE PERFORM 9999-ABEND-PARA THRU 9999-EXIT END-EVALUATE. 1000-EXIT. EXIT. 2000-PROCESS. READ CMSTR. EVALUATE WS-CMSTR-FST WHEN 00 CONTINUE WHEN 10 SET WS-CMSTR-EOF-YES TO TRUE GO TO 2000-EXIT WHEN OTHER DISPLAY 'ERROR IN READING INPUT FILE: ' DISPLAY WS-CMSTR-FST MOVE WS-CMSTR-FST TO WE-ERR-CODE PERFORM 9999-ABEND-PARA THRU 9999-EXIT END-EVALUATE IF CM2-RECORD-TYPE-SOLD-TO MOVE CM2-ENTERING-BRANCH TO WS-EB PERFORM 3000-READ THRU 3000-EXIT UNTIL WS-CTAB-EOF-YES END-IF. 2000-EXIT. EXIT. 3000-READ. MOVE WS-EB TO VSAM-WHSE-CD. MOVE 'WHSE' TO VSAM-WHSE-ID. READ CTAB. EVALUATE WS-CTAB-FST WHEN 00 MOVE WHSE-DIV-CODE TO WS-DIV PERFORM 4000-REWRITE-CMF THRU 4000-EXIT WHEN 10 SET WS-CTAB-EOF-YES TO TRUE GO TO 3000-EXIT WHEN OTHER DISPLAY 'ERROR IN READING TABLE FILE: ' DISPLAY WS-CTAB-FST MOVE WS-CTAB-FST TO WE-ERR-CODE PERFORM 9999-ABEND-PARA THRU 9999-EXIT END- EVALUATE. 3000- EXIT. EXIT. 4000-REWRITE- CMF. IF WS-DIV = 250 OR 252 MOVE 'F' TO CM2-FREIGHT- TYPE MOVE 1 TO CM2-FREIGHT-THRESHOLD- AMT ADD +1 TO WS-CMF-RECS- REWRITTEN REWRITE CM2-SOLD-TO- RECORD DISPLAY 'RECORD UPDATED' END- IF. * EVALUATE WS-CMSTR- FST * WHEN 00 * CONTINUE * WHEN OTHER * DISPLAY 'FILE NOT UPDATED' * DISPLAY WS-CMSTR- FST * MOVE WS-CMSTR-FST TO WE-ERR-CODE * PERFORM 9999-ABEND-PARA THRU 9999-EXIT * GO TO 4000-EXIT * END-EVALUATE. 4000-EXIT. EXIT. 5000-CLOSE. CLOSE CMSTR CTAB. 5000-EXIT. EXIT. 9999-ABEND-PARA. COMPUTE WE-ABEND-CODE = WC-ABEND-900 + WE-ERR-CODE CALL 'ILBOABN0' USING WE-ABEND-CODE GO TO 5000-CLOSE. 9999-EXIT. EXIT. 5000-CLOSE. CLOSE CMSTR CTAB. 5000-EXIT. EXIT. 9999-ABEND-PARA. COMPUTE WE-ABEND-CODE = WC-ABEND-900 + WE-ERR-CODE CALL 'ILBOABN0' USING WE-ABEND-CODE GO TO 5000-CLOSE. 9999-EXIT. EXIT. //this program is giving maxcc=0, but not updating..

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