Answer / swapna

Hi this question was asked in my interview.
Ans is :

a=a+b;
b=a-b;
a=a-b;

Any other solution?

Answer / guest

use xor to swap

a = a^b
b= a^b
a= a^b

Answer / somasekhar

Ans is :

a=a*b;
b=a/b;
a=a/b;

Answer / kiran

a=a+b;
b=a-b;
a=a-b

Answer / mohit

x = x + y;

y = x - y;

x = x - y;

Answer / bruce tuskey

Only the Xor answer (#2) is correct (in cases where the
variables are the same size). With all the other answers,
you could run into over/under flow problems.
A = 01111111
B = 01111101

A = A^B = 00000010
B = A^B = 01111111 (Original A)
A = A^B = 01111101 (Original B)

Answer / partha

a=b-a+(b=a);

Answer / gowtham

2 one will work correct

Answer / pavan.

void main()
{
int a,b;
printf("Enter two number : ");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("The swap number is : %d %d",a,b);
getch();
}

Answer / yash

Answer no 12 is wrong. the logic fails when a=0;

union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0

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