Answer / er

Only #2 will work. The others may over/under flow.

Answer / krishna

a=(a>b?a:b)

Answer / ankush

using ref keyword we can swap 2 number's

emaple
class swap
{
public void add(ref int a,ref int b)
{
int z;
z=a;
a=b;
b=z;
}
}
class swapdemo
{
static void main()
{
int x=10,y=5;
ankush obj=new ankush();
Console.writeline{"befor value's"+a+","+b};
obj.swap(ref x, ref y);
Console.writeline("after values"+a+","+b);
}
}

Answer / vinay_csjm

a=5,b=10
a=a-b;
b=a+b;
a=a+b;

void main() { static int i=5; if(--i){ main(); printf("%d ",i); } }

1 Answers  

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Given only putchar (no sprintf, itoa, etc.) write a routine putlong that prints out an unsigned long in decimal.

6 Answers   Fusion Systems GmbH,

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#include<stdio.h> main() { FILE *ptr; char i; ptr=fopen("zzz.c","r"); while((i=fgetch(ptr))!=EOF) printf("%c",i); }

1 Answers  

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main() { register int a=2; printf("Address of a = %d",&a); printf("Value of a = %d",a); }

3 Answers  

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Write a program to receive an integer and find its octal equivalent?

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main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

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plz send me all data structure related programs

2 Answers  

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Printf can be implemented by using __________ list.

3 Answers  

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main() { int i=0; while(+(+i--)!=0) i-=i++; printf("%d",i); }

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I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..

0 Answers  

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How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

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void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %d\n",++i); }

3 Answers  

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