Answer / dani

Actually I compiled this and ran it unix and it just prints out a warning, not an error:
"warning: initializer-string for array of chars is too long"

The programme prints the initial array without the last character (because of the '\0' special character):
"HELL �"

Answer / smk

too many intializer for a[4](warning)

Answer / susie

Answer :

Compiler error: Too many initializers

Explanation:

The array a is of size 4 but the string constant requires 6
bytes to get stored.

Cluster head selection in Wireless Sensor Network using C programming language.

0 Answers  

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#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }

3 Answers   Hexaware,

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In a gymnastic competition, scoring is based on the average of all scores given by the judges excluding the maximum and minimum scores. Let the user input the number of judges, after that, input the scores from the judges. Output the average score. Note: In case, more than two judges give the same score and it happens that score is the maximum or minimum then just eliminate two scores. For example, if the number of judges is 5 and all of them give 10 points each. Then the maximum and minimum score is 10. So the computation would be 10+10+10, this time. The output should be 10 because 30/3 is 10.

0 Answers   TCS,

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

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main() { static char names[5][20]={"pascal","ada","cobol","fortran","perl"}; int i; char *t; t=names[3]; names[3]=names[4]; names[4]=t; for (i=0;i<=4;i++) printf("%s",names[i]); }

2 Answers  

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What is the hidden bug with the following statement? assert(val++ != 0);

1 Answers  

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main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

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main() { struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }

1 Answers  

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Finding a number which was log of base 2

1 Answers   NetApp,

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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

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main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

2 Answers  

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how to print 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 using any loop(for or while) only once(only 1 loop) and maximum 2 variables using C.

19 Answers   Cap Gemini, Infosys,

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