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main( )
{
void *vp;
char ch = ‘g’, *cp = “goofy”;
int j = 20;
vp = &ch;
printf(“%c”, *(char *)vp);
vp = &j;
printf(“%d”,*(int *)vp);
vp = cp;
printf(“%s”,(char *)vp + 3);
}
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Answer / susie
Answer :
g20fy
Explanation:
Since a void pointer is used it can be type casted to any
other type pointer. vp = &ch stores address of char ch and
the next statement prints the value stored in vp after type
casting it to the proper data type pointer. the output is
‘g’. Similarly the output from second printf is ‘20’. The
third printf statement type casts it to print the string
from the 4th value hence the output is ‘fy’.
| Is This Answer Correct ? | 4 Yes | 0 No |
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