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void main()

{

char a[]="12345\0";

int i=strlen(a);

printf("here in 3 %d\n",++i);

}

Answers were Sorted based on User's Feedback



void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %..

Answer / susie

Answer :

here in 3 6

Explanation:

The char array 'a' will hold the initialized string, whose
length will be counted from 0 till the null character. Hence
the 'I' will hold the value equal to 5, after the
pre-increment in the printf statement, the 6 will be printed.

Is This Answer Correct ?    18 Yes 4 No

void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %..

Answer / lucky varshney

here in 3
7

Is This Answer Correct ?    4 Yes 6 No

void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %..

Answer / ravneet kaur

as this is a character array and would have string in double
quotes so this code shows an error i.e. *char wont changes
to *int.

Is This Answer Correct ?    0 Yes 5 No

Post New Answer

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