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write the regular expression for date format of mm/dd/yy?
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Answer / rajesh
[1-9]|1[0-2]/[1-9]|[1-2][0-9]|3[0-1]/19[0-9][0-9]|2[0-9][0-9][0-9]
More food for thought valid from 1900 to 2999.
| Is This Answer Correct ? | 13 Yes | 0 No |
Answer / rajesh
Pavani your point is correct
Here is the format for the input.
MM will be 1 to 12 "[1-9]|1[0-2]"
DD will be 1 to 31 "[1-9]|[1-2][0-9]|3[0-1]"
YY will be "[0-9][0-9]"
Hence MM/DD/YYYY will be
"[1-9]|1[0-2]/[1-9]|[1-2][0-9]|3[0-1]/[0-9][0-9]"
| Is This Answer Correct ? | 10 Yes | 5 No |
Answer / hetal
Regular experession can also be written in qtp as follow:
(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / falak
^(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d$
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / lak
^([1-9]|0[1-9]|1[0-2])[- / .]([1-9]|0[1-9]|1[0-9]|2[0-9]|3
[0-1])[- / .](1[9][0-9][0-9]|2[0][0-9][0-9])$
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sai shankar
(0[1-9]|1[0-2])[./-](0[1-9]|1[0-9]|2[0-9]|[a-z])[./-]([0-9]{4})
| Is This Answer Correct ? | 0 Yes | 0 No |
Thanks ranu & pratap.
But given regular expressions are accepting the invalid
date like 19/39/2000
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / ranu rathore
[0-1][0-2]/[0-3][0-9]/[0-2][0-9][0-9][0-9]
| Is This Answer Correct ? | 3 Yes | 6 No |
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