#if something == 0
int some=0;
#endif
main()
{
int thing = 0;
printf("%d %d\n", some ,thing);
}
Answer / susie
Answer :
0 0
Explanation
This code is to show that preprocessor expressions are not
the same as the ordinary expressions. If a name is not known
the preprocessor treats it to be equal to zero.
Is This Answer Correct ? | 7 Yes | 2 No |
Is the following code legal? struct a { int x; struct a *b; }
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main() { int i=5; printf("%d%d%d%d%d%d",i++,i--,++i,--i,i); }
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13 Answers Intel, Microsoft, TCS,
why java is platform independent?
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PROG. TO PRODUCE 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1
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