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main()
{
int i=0;
while(+(+i--)!=0)
i-=i++;
printf("%d",i);
}
- 9 Answers
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Answer / susie
Answer :
-1
Explanation:
Unary + is the only dummy operator in C. So it has no effect
on the expression and now the while loop is, while(i--!=0)
which is false and so breaks out of while loop. The value –1
is printed due to the post-decrement operator.
| Is This Answer Correct ? | 75 Yes | 2 No |
Answer / govind verma
output will be -1.... because inwhile +(+i--)!=0 () have higher precedence then control goes to in parenthses and unary plus and ++ have the same precedece in table then we chek the associativty which is right to left i++ is evaluate first then the value of i will not chang withn a same expression because its a post fix increment now expression become +(+0)!=0 and unary plus have no effect then expression look lyk 0!=0 this condition is false then while block of code will not execute and nw i become -1 and we try to print like this printf("%d",-1); then output will -1
| Is This Answer Correct ? | 9 Yes | 2 No |
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C Code 
