Answer / susie

Answer :

0 0 0 0

Explanation:

The variable "I" is declared as static, hence memory for I
will be allocated for only once, as it encounters the
statement. The function main() will be called recursively
unless I becomes equal to 0, and since main() is recursively
called, so the value of static I ie., 0 will be printed
every time the control is returned.

What is the problem with the following code segment? while ((fgets(receiving array,50,file_ptr)) != EOF) ;

1 Answers  

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Write a prog to accept a given string in any order and flash error if any of the character is different. For example : If abc is the input then abc, bca, cba, cab bac are acceptable, but aac or bcd are unacceptable.

5 Answers   Amazon, Microsoft,

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main() { int i = 0xff ; printf("\n%d", i<<2); } a. 4 b. 512 c. 1020 d. 1024

2 Answers   HCL,

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void main() { int i=5; printf("%d",i++ + ++i); }

3 Answers  

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main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  

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Given an array of size N in which every number is between 1 and N, determine if there are any duplicates in it. You are allowed to destroy the array if you like.

21 Answers   ABC, eBay, Goldman Sachs, Google, HUP, Microsoft, TATA,

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main() { int i=1; while (i<=5) { printf("%d",i); if (i>2) goto here; i++; } } fun() { here: printf("PP"); }

1 Answers  

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main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }

1 Answers  

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Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution)

7 Answers   Microsoft,

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main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); } int i;

1 Answers  

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main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

2 Answers  

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main() { int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p } a. Runtime error. b. 1.00000 c. Compile error d. 0.00000

3 Answers   HCL,

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