Answer / susie

Answer :

Runtime error : Stack overflow.

Explanation:

main function calls itself again and again. Each time the
function is called its return address is stored in the call
stack. Since there is no condition to terminate the function
call, the call stack overflows at runtime. So it terminates
the program and results in an error.

write the function. if all the character in string B appear in string A, return true, otherwise return false.

11 Answers   Google,

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main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }

1 Answers  

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main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

3 Answers   HCL,

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main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }

6 Answers  

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Develop a routine to reflect an object about an arbitrarily selected plane

0 Answers  

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main() { char * strA; char * strB = I am OK; memcpy( strA, strB, 6); } a. Runtime error. b. I am OK c. Compile error d. I am O

4 Answers   HCL,

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What is "far" and "near" pointers in "c"...?

3 Answers  

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#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above

3 Answers   HCL,

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#define clrscr() 100 main() { clrscr(); printf("%d\n",clrscr()); }

2 Answers  

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String reverse with time complexity of n/2 with out using temporary variable.

10 Answers   NetApp, Symantec,

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In the following pgm add a stmt in the function fun such that the address of 'a' gets stored in 'j'. main(){ int * j; void fun(int **); fun(&j); } void fun(int **k) { int a =0; /* add a stmt here*/ }

1 Answers  

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main() { int i=-1; +i; printf("i = %d, +i = %d \n",i,+i); }

1 Answers  

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