main()
{
int x=5;
for(;x!=0;x--) {
printf("x=%d\n", x--);
}
}
a. 5, 4, 3, 2,1
b. 4, 3, 2, 1, 0
c. 5, 3, 1
d. none of the above
Answers were Sorted based on User's Feedback
Answer / guest
d) Infinite loop as x is decremented twice, it never be 0
and loop is going on & on
Is This Answer Correct ? | 13 Yes | 0 No |
Answer / ajit
first error in 4 step as syntax error
this is so that for(x!=0;x--) answer is d becoze here
not defined x=?
Is This Answer Correct ? | 0 Yes | 10 No |
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