Answer / aneesh sagar

void main()
{
int a[10],i,j,pos;
printf("enter the element in the array:\n");
for(i=0;i<10;i++)
scanf("%d",&a[i]);
printf("enter the position to be deleted\n");
scanf("%d",&pos);
i=0;
while(i!=pos-1)
i++;
for(j=i;j>10;j++)
a[j]=a[i+1];
i++;
printf("now the array is");
for(i=0;i<10;i++)
printf("%d",a[i]);

Answer / jessybhatia

void main()
{
int a[50],i,pos,size;
clrscr();
printf("\nEnter size of the array: ");
scanf("%d",&size);
printf("\nEnter %d elements in to the array: ",size);
for(i=0;i
scanf("%d",&a[i]);
printf("\nEnter position where to delete: ");
scanf("%d",&pos);
i=0;
while(i!=pos-1)
i++;
while(i<10)
{
a[i]=a[i+1];
i++;
}

#define assert(cond) if(!(cond)) \ (fprintf(stderr, "assertion failed: %s, file %s, line %d \n",#cond,\ __FILE__,__LINE__), abort()) void main() { int i = 10; if(i==0) assert(i < 100); else printf("This statement becomes else for if in assert macro"); }

1 Answers  

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find simple interest & compund interest

2 Answers  

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main() { char *cptr,c; void *vptr,v; c=10; v=0; cptr=&c; vptr=&v; printf("%c%v",c,v); }

1 Answers  

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#define a 10 int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } void foo() { #undef a #define a 50 }

3 Answers  

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#define max 5 #define int arr1[max] main() { typedef char arr2[max]; arr1 list={0,1,2,3,4}; arr2 name="name"; printf("%d %s",list[0],name); }

1 Answers  

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main() { int i=5,j=10; i=i&=j&&10; printf("%d %d",i,j); }

1 Answers  

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struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error

3 Answers   HCL,

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4. Main() { Int i=3,j=2,c=0,m; m=i&&j||c&I; printf(“%d%d%d%d”,I,j,c,m); }

2 Answers   Broadridge,

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main() { int i=3; switch(i) { default:printf("zero"); case 1: printf("one"); break; case 2:printf("two"); break; case 3: printf("three"); break; } }

1 Answers  

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How do you verify if the two sentences/phrases input is an anagram using predefined functions in string.h and by using arrays?

0 Answers  

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char *someFun1() { char temp[ ] = “string"; return temp; } char *someFun2() { char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’}; return temp; } int main() { puts(someFun1()); puts(someFun2()); }

2 Answers  

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main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

1 Answers   CSC,

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