Answer / xxx

compilation error at the line number 4.

Answer / sironmnai

1,2,0,1

#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }

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Cau u say the output....?

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

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main() { int i; printf("%d",scanf("%d",&i)); // value 10 is given as input here }

2 Answers   IBM,

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why nlogn is the lower limit of any sort algorithm?

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How to use power function under linux environment.eg : for(i=1;i<=n;i++){ pow(-1,i-1)} since it alerts undefined reference to 'pow'.

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What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

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main() { static char names[5][20]={"pascal","ada","cobol","fortran","perl"}; int i; char *t; t=names[3]; names[3]=names[4]; names[4]=t; for (i=0;i<=4;i++) printf("%s",names[i]); }

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main() { extern i; printf("%d\n",i); { int i=20; printf("%d\n",i); } }

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#include<stdio.h> main() { register i=5; char j[]= "hello"; printf("%s %d",j,i); }

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main() { unsigned int i=65000; while(i++!=0); printf("%d",i); }

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void main() { int i=i++,j=j++,k=k++; printf(“%d%d%d”,i,j,k); }

1 Answers  

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