There are five thieves, each loot a bakery one after the
other such that the first one takes 1/2 of the total no.
of the breads plus 1/2 of a bread. Similarly 2nd, 3rd,4th
and 5th also did the same. After the fifth one no. of
breads remained are 3. Initially how many breads were there?
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Answer / anbu
Friends,
The Answer given by 'Gaurav Sharma' is correct and
the approach (bottom to top) suggested by 'Shailesh' is
good. But with minor correction we can arrive the solution
using this approach:
After 5th loot, No. of breads left = 3
after 4th loot, no. of breads left = (3+0.5)x2 = 7
after 3rd loot, no. of breads left = (7+0.5)x2 = 15
after 2nd loot, no. of breads left = (15+0.5)x2 = 31
after 1st loot, no. of breads left = (31+0.5)x2 = 63
So, before 1st loot, no. of breads left = (63+0.5)x2 = 127
| Is This Answer Correct ? | 40 Yes | 10 No |
Answer / guest
127 is the correct answer.
When the last thief comes the number of bread will be 7.
Later on going upwards it takes the formula
2x+1 ie 2*7+1 =15 no will be there when Fourth thief comes
and so on.
for third thief 2*15+1 ie 31 bread will be there
for second thief 2*31+1 ie 63 bread will be there
for first thief 2*63+1 ie 127 bread will be there
| Is This Answer Correct ? | 26 Yes | 7 No |
Answer / randheer chauhan
3---> 3*2+0.5=6.5 ----> 6.5*2+0.5=13.5 ---
---> 13.5*2 + 0.5=27.5 ----> 27.5*2+0.5=55.5----
---> 55.5*2=111
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / shailesh
guyz its better to go bottom to top in this prob
After 5th man 3 bread remained implies twice no. of (breads
minus half) available b4 him
there are (3-0.5) x 2 = 5 breads available before him
for 4th man
(5-0.5)x2=9
for 3rd man
(9-0.5)x2=17
for 2nd man
(17-0.5)x2=33
for 1st man
(33-0.5)x2=65
dats total 65 breads available
| Is This Answer Correct ? | 5 Yes | 8 No |
Answer / j
when the fifth one take half of the total no of breads and
1/2 of a bread, it cant be the remeining no of bread is 3
| Is This Answer Correct ? | 1 Yes | 8 No |
Answer / chandra prakash garg
I think initialially total bread were 225.
How:
Let it be x.
(x+1)/2 + (x+3)/4 + (x+7)/8 + (x+15)/16 + (x+31)/32 + 3 = x.
Solve the equation, you will get the answer.
| Is This Answer Correct ? | 1 Yes | 9 No |
Answer / niraj
remaining bread= 3
5th thief loot 1/2totatl no of breads & 1/2 of bread
means breads were 3+3+1/2=6&1/2
similarly
4th thief loot 6.5+6.5+.5=13.5
3rd 13.5+13.5+.5=27.5
2nd 27.5+27.5+.5=55.5
so at the time of 1st thief
no. of breads were 55.5+55.5+.5= 111.5
| Is This Answer Correct ? | 2 Yes | 12 No |
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