int a=1,b=2,c=3;
printf("%d,%d",a,b,c);
What is the output?
- 14 Answers
- 28005 Views
- Verifone, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / jaya prakash
1,2
because arguments of functions stored in stock
in stock stored as
"%d,%d"
a
b
c
in printf fn,
args popped out from stack
first "%d,%d" is popped
it find two int involved by %d in the control string
so two more args popped out
a,b
after popping the addr's then the values in that location
printed.(1,2)
| Is This Answer Correct ? | 28 Yes | 3 No |
Answer / sateeshbabu aluri
o/p will be: 1 2 only
3 will be ommited because there is no conversion operator
in printf.
| Is This Answer Correct ? | 13 Yes | 0 No |
Answer / poornima
Actually, Stack follows Last In First Out(LIFO) style.No
doubt in tht.
In code, there is only two format specifier(ie., 2 %d) tht
will corresponds to first two variables.
Elements are pushed from right to left fashion in variable
declaration part.
In stack, c is bottom-most element & a is top-most element.
so,by code a is popped first then b.so, it will print 1,2.
| Is This Answer Correct ? | 8 Yes | 4 No |
Ans:1,2
because arguments of functions stored in stack in FIFO order
So Var a enters 1st so it will out (popped)1st too as it's
STACK's property.
| Is This Answer Correct ? | 10 Yes | 7 No |
what is the stackpointer
Can we change the value of constant variable in c?
progrem to generate the following series 1 12 123 1234 12345
Write a program to swap two numbers without using third variable?
Why do we use stdio h and conio h?
What is the use of a ‘ ’ character?
find the output? void r(int a[],int c, int n) { if(c>n) { a[c]=a[c]+c; r(a,++c,n); r(a,++c,n); } } int main() { int i,a[5]={0}; r(a,0,5); for(i=0;i<5;i++) printf("\n %d",a[i]); getch(); }
what is use#in c
What is the difference between char array and char pointer?
why use functions a) writing functions avoids rewriting the same code over and over b) using functions it becomes easier to write programs and keep track of what they are doing c) a & b d) none of the above
Give me basis knowledge of c , c++...
What is the result main() { char c=-64; int i=-32 unsigned int u =-16; if(c>i){ printf("pass1,"); if(c<u) printf("pass2"); else printf("Fail2");} else printf("Fail1); if(i<u) printf("pass2"); else printf("Fail2") } a)Pass1,Pass2 b)Pass1,Fail2 c)Fail1,Pass2 d)Fail1,Fail2 e)none
C 
