Answer / nipun

#include<stdio.h>
#include<conio.h>

void main()
{
int var;
int count=0;
int n=0;
clrscr();
while(n<10)
{
printf("Enter the number:");
scanf("%d",&var);
if(var%2 == 0)
{
count++;
n++;
}
else
{
n++;
continue;
}
}
printf("Even numbers present:%d",count);
getch();
}

Answer / sansiri

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=0;
int count=0;
printf("\n Enter the 10 integer numbers");
while(i<10)
{
scanf("%d",&n);
if(n%2==0)
{
count++;
}
i++;
}
printf("\nCount of even numbers:%d",count);
getch();
}

printf

void main() { int i=7; printf("N= %*d",i,i); }

6 Answers   HCL,

---

#include"stdio.h" #include"conio.h" void main() { int a; printf("\n enter a number:"); scanf("%c\n"); getch(); }

12 Answers   HCL,

---

main() { char c; for(c='A';c<='Z';c++) getch(); }

9 Answers  

---

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }

19 Answers  

---

errors are known as?

3 Answers   EX, State Bank Of India SBI,

---

what is the error in the following code: main() { int i=400,j; j=(i*i)/i; }

4 Answers  

---

Assume that the int variables i and j have been declared, and that n has been declared and initialized. Write code that causes a "triangle" of asterisks of size n to be output to the screen. Specifically, n lines should be printed out, the first consisting of a single asterisk, the second consisting of two asterisks, the third consistings of three, etc. The last line should consist of n asterisks. Thus, for example, if n has value 3, the output of your code should be * ** *** You should not output any space characters. Hint: Use a for loop nested inside another for loop.

2 Answers   HCL,

---

void main() { int i=5; printf("%d",i+++++i); }

14 Answers   HCL,

---

UINT i,j; i = j = 0; i = ( i++ > ++j ) ? i++ : i--; explain pls....

5 Answers  

---

what is run time error?

7 Answers  

---

what are the techniques for reducing the fragility of a memory bug?

1 Answers  

---

2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]

0 Answers  

---