Answer / pushkar kalantri

#include<stdio.h>
#include<string.h>

void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
//clrscr();

printf("Enter coded value: ");
scanf("%s",ip);

// printf("\nur entered code = %s",ip);
printf("\nUr price is = ");


for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
}
//compiled by GCC

Answer / levixnu

#include<stdio.h>
#include<string.h>
#include<conio.h>

void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
clrscr();

printf("Enter coded value: ");
scanf("%s",ip);

printf("\nur entered code = %s",ip);
printf("\nUr price is = ");


for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
getch();
}

Answer / roxy

#include<stdio.h>
#include<string.h>

main()
{
char v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'};
char v2[11]={'0','1','2','3','4','5','6','7','8','9','\0'};

int n;
clrscr();

printf("Enter coded value: ");
scanf("%s",v1);

n=strncpy(v1, v2, 1);

v2[1]='\0';

printf("\nTag Price: %s ",v2);

getch();
}

I'm having trouble with coming up with the correct code. Do I need to put a loop? Please let me know if I'm on the right track and what areas I need to correct. I still don't have a good grasp on this programming stuff. Thanks =) The assignment was to write a program using string functions that accepts a coded value of an item and displays its equivalent tag price. The base of the keys: 0 1 2 3 4 5 6 7 8 9 X C O M P U T E R S Sample I/O Dialogue: Enter coded value: TR.XX Tag Price : 68.00

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