Answer / sara

M20=1:1.5:3
Dry volume of concrete in 1cum=1.54
Cement Quantity=1.54/(1+1.5+3)
=0.28cum
=0.28/0.035=8 bags
=0.28*1440=403.2kg

same way we can calculate M25 cncrete

Answer / awais goraya

M25
Cement =320 kg/cu.m
fine aggregate= 751 kg/cu.m
coarse aggregate =
20 mm = 977 kg/cu.m
10 mm =380 kg/cu.m
w/c ratio = 0.43
quantity of water= 138 liter

M20
Cement =290kg/cu.m
fine aggregate= 696 kg/cu.m
coarse aggregate =
20 mm = 1029 kg/cu.m
10 mm =400 kg/cu.m
w/c ratio = 0.5
quantity of water = 145 liter

Answer / imran

54% add for wet dry volume and wastage .
dry volume -1x1.54= 1.54m3 m 15(1:2:4)
so, cement 1/7x1.54= ? nd then 1/0.0347x?=? bsgs
sand-2/7x1.54=? m3
coarse agg.-4/7x1.54=?m3

Answer / dalchands

M20=1:1.5:3
Dry volume of concrete in 1cum=1.52
Cement Quantity=1.52/5.5
=0.28cum
=0.28/0.035=8 bags
=0.28*1440=403.2kg
M25=1:1:2
Dry Volume = 1.52/4
Cement = 570.00 kg

Answer / mohammedazharuddin

QUANTITY OF CEMENT IN 1CUM FOR M20,M25 IS 320KG AND 340KG

NO.OF BAGS = 6.2 FOR M20 AND 7 FOR M25

RATIO OF M20,M25 = 1:1.5:3,1:1:2

Answer / senthil kumar

M10-3.4nos of bags of cement
M15-6.2
M20-6.8
M25-7.5
M30-8.5
M35-9
M40-10

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Respected Sir, I am from a hilly place called Darjeeling ,I have constructed house of 9 column out of which 4 of the column is under water , i have put rcc slab on top and on top of the rcc slab i have construced two room house with bricks and light roof , now i am planning to change the light roof with rcc slab for the two room, my main concern is will the column under water will hold the load of the new rcc slab coz it already 10 to 12 yrs old , i dont know what to do , can u advice me regarding this matter, weather to leave the upper floor roof light or make it rcc slab.(If i put the slab , it will require 45bags of cement and u calculate how much of steel and sand and pebbles) thanks with regard Anand

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