Answer / sara

M20=1:1.5:3
Dry volume of concrete in 1cum=1.54
Cement Quantity=1.54/(1+1.5+3)
=0.28cum
=0.28/0.035=8 bags
=0.28*1440=403.2kg

same way we can calculate M25 cncrete

Answer / awais goraya

M25
Cement =320 kg/cu.m
fine aggregate= 751 kg/cu.m
coarse aggregate =
20 mm = 977 kg/cu.m
10 mm =380 kg/cu.m
w/c ratio = 0.43
quantity of water= 138 liter

M20
Cement =290kg/cu.m
fine aggregate= 696 kg/cu.m
coarse aggregate =
20 mm = 1029 kg/cu.m
10 mm =400 kg/cu.m
w/c ratio = 0.5
quantity of water = 145 liter

Answer / imran

54% add for wet dry volume and wastage .
dry volume -1x1.54= 1.54m3 m 15(1:2:4)
so, cement 1/7x1.54= ? nd then 1/0.0347x?=? bsgs
sand-2/7x1.54=? m3
coarse agg.-4/7x1.54=?m3

Answer / dalchands

M20=1:1.5:3
Dry volume of concrete in 1cum=1.52
Cement Quantity=1.52/5.5
=0.28cum
=0.28/0.035=8 bags
=0.28*1440=403.2kg
M25=1:1:2
Dry Volume = 1.52/4
Cement = 570.00 kg

Answer / mohammedazharuddin

QUANTITY OF CEMENT IN 1CUM FOR M20,M25 IS 320KG AND 340KG

NO.OF BAGS = 6.2 FOR M20 AND 7 FOR M25

RATIO OF M20,M25 = 1:1.5:3,1:1:2

Answer / senthil kumar

M10-3.4nos of bags of cement
M15-6.2
M20-6.8
M25-7.5
M30-8.5
M35-9
M40-10

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