A man speaks the truth 3 out of 4 times. He throws a die
and reports it to be a 6. What is the probability of it
being a 6?
(a) 3/8
(b) 5/8
(c) 3/4
(d) None of the above
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Answer / kishore
prob. of getting 6 in a die p(e1)=1/6
prob. of not getting 6 in a die p(e2)=1-(1/6)=5/6
prob. of the man getting 6 in a die and reporting it as 6
i.e. truth p(e/e1)=3/4
prob. of the man NOT getting 6 in a die and reporting it as
6 i.e. lying p(e/e2)=1-(3/4)=1/4
P= p(e1)p(e/e1)
------------------------
p(e1)p(e/e1)+p(e2)p(e/e2)
p= 1/6*3/4
--------------------
(1/6*3/4)+(5/6*1/4)
p= 3/8
Answer is (a)
| Is This Answer Correct ? | 125 Yes | 7 No |
Answer / cryolife
Here the probability of a die being a 6 is 3/8.
Ans is (a).
| Is This Answer Correct ? | 35 Yes | 15 No |
Answer / hynynu
prob. of getting 6 in a die p(e1)=1/6
prob. of not getting 6 in a die p(e2)=1-(1/6)=5/6
prob. of the man getting 6 in a die and reporting it as 6
i.e. truth p(e/e1)=3/4
prob. of the man NOT getting 6 in a die and reporting it as
6 i.e. lying p(e/e2)=1-(3/4)=1/4
P= p(e1)p(e/e1)
------------------------
p(e1)p(e/e1)+p(e2)p(e/e2)
p= 1/6*3/4
--------------------
(1/6*3/4)+(5/6*1/4)
p= 3/8
Answer is (a)
| Is This Answer Correct ? | 7 Yes | 1 No |
Answer / saravanan.s
(d) None of the above
because the probability coming 6 in one dice is 1/6
but the person is speaking truth of 3/4 probability
so simply
(3/4)*(1/6)=1/8
and 3/8=0.375
5/8=0.625
3/4=.75
probability of getting a six is 1/6=.1667
do u think that THE PROBABILITY FOR "SAYING THE TRUTH" &
"FALLING SIX IN THE DICE" would me more than the PROBABILITY
FOR FALLING 6 IN A THROW IN DICE .
| Is This Answer Correct ? | 3 Yes | 5 No |
Answer / mohsin
P(it is six|reports six) = P(it is 6, reports six)/P(reports
six) = [3/4*1/6] / [(3/4*1/6) + (1/4*5/6*1/5)] = 3/4
(c)
| Is This Answer Correct ? | 20 Yes | 25 No |
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