Answer / uday

str="POWER STAR PAVAN"
counter=0
For i=1 to len(str)
strChar=mid(str,i,1)
If strChar="A" Then
counter=counter+1
End If
Next
msgbox counter

Answer / pavani prasad naidu

Dim oArray
Dim ochr
oStr="POWER STAR PAVAN"
ochr="A"

oArray=split(oStr,ochr)
print ubound(oArray)

Answer / ram

str="POWER STAR PAVAN"


len1=len(str)


str=replace(str,"a", "")


len2=len(str)

a=len1-len2


msgbox a

Answer / goms

Val="POWER STAR PAVAN"
If instr(Val,"A")>0 then
Msgbox "Pass"
Else
Msgbox "Fail"
End IF

Note: If instr function returns the position of the value.
If it is greater than 0, the letter is in the particular
variable

Answer / madhulika

function VerifyLetters(S_String,S_Pattern,MatchStr)
Set OReg = new RegExp
Set S_Pattern = OReg.Pattern
OReg.IgnoreCase = True
OReg.Global = MatchStr
Set Matches = OReg.Test(S_String)
MatchFound = Matches.count
VerifyLetters = MatchFound
End Function
-------------------------------------
val = "Power star pavan"
'Calling function
msgbox VerifyLetters(val,"A",True)

Answer / seru

str="POWER STAR PAVAN"

Number_of_A=Len(str)-Len(Replace(str,"A",""))
msgbox Number_of_A

Answer is 3

Answer / ravi

str="POWER STAR PAVAN"
len1=len(str)
msgbox len1
str=replace(str,"A", "")
len2=len(str)
msgbox len2
a=len1-len2
msgbox a

hi i have one doubt i have 4 yrs exp in testing and iam working one mnc in north but i have completed my degree correspodene is the companies are accept in south side some people are tellig they won't agree but i need correct answer plz let me know which companies are taking and not taking thanks in advance

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