#define CUBE(x) (x*x*x)
main()
{ int a,b=3;
a=cube(b++);
printf("%d %d",a,b);
}
What should be the value of a and b? My calc a=4 but syst
a=6 how pls tell me if you know it?
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Answer / maitri
Couple of things:
a. macro is expanded as (x++ * x++ * x++)
b. what we have here is a postfix operator
so a = CUBE(3)=3*3*3
and b = 6 (incremented thrice)
| Is This Answer Correct ? | 53 Yes | 14 No |
Answer / vasanth
since macro is expanded like (x++ * x++ * x++) = (3 * 4 *
5) => a = 60
and final value of b = 5++ => 6
ans : 60, 6
| Is This Answer Correct ? | 31 Yes | 15 No |
Answer / pratap keshari
The output will be 27 6
b++ will be replaced as 3++ in the macro and these values
will be evaluated after the macro execution.Hence first it
will evaluate to 3's cube and then increment 3 three times
| Is This Answer Correct ? | 10 Yes | 7 No |
Answer / p. smith
27 4 is the output.
the call to the macro sets a = b*b*b with b = 3, 3 cubed is 27
then b is incremented to 4 after the macro call
| Is This Answer Correct ? | 22 Yes | 21 No |
Answer / riadh khedhiri
the output on a my box:
Linux 2.6.32-22-generic-pae #36-Ubuntu SMP Thu Jun 3 23:14:23 UTC 2010 i686 GNU/Linux with gcc (Ubuntu 4.4.3-4ubuntu5) 4.4.3
a = 27
b = 6
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / prabhaaa
since macro is expanded like (x++ * x++ * x++) = (3 * 4 *
5) ..here the value increments in each of its position. first [3 *3++*(3++)++] = [3*4*4++]
= [3*4*5]
a = 60
and here b increments three times .3++=4, 4++=5 ,5++=6.
final value of b = 5++ => 6
ans : 60, 6
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / ashwini
above code have error.If used CUBE instead of cube then
output will be
A = CUBE(B++ * B++ * B++)
as ++ is post increment plus operator so A = 27 and then B
gets incremented three times so B = 6
| Is This Answer Correct ? | 3 Yes | 4 No |
a will be 27 and b will be 6.
since the cube root of 3 is assigned to 'a' it will contain the value 27, and after this 'b' will gets incremented 3 times (x++ * x++ * x++) hence 'b' will become 6
so a = 27 b= 6
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / alan
it depends on the compiler
(x++ * x++ * x++) ==>correct.
the question is when x++?
Note the second time x++, it use the value of x or x++ of
the first x++?
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / jayprakash singh
in question we use #define CUBE(X) (X*X*X) but in main
function we use a=cube(b++);
what is this i think it is wrong it must be error at
compile time.
if we use a=CUBE(b++); instead of a=cube(b++);then output
will be 27 6
becuse 1st (3*3*3)=27 then increment of value b thrice so b=6
| Is This Answer Correct ? | 1 Yes | 5 No |
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#define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%d %d",a,b); } What should be the value of a and b? My calc a=4 but syst a=6 how pls tell me if you know it?
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