Answer / arnab maji

Hey Susie,

The ## is a concatenation operator,
When you pass the two arguments they get concatenated as

i/p --> f(g,g2) g##g2
o/p --> gg2

hence
f(var,12) will give us var12

effectively the printf statement gets modified as

printf("%d",f(var,12)); --> printf("%d",var12);

hence the output is 100 ie the value of var12.

Answer / susie

Answer :

100

Answer / vignesh1988i

the answer is 10012, the printf statement must be :

printf("%d",f(var12,12));

the number 12 will be concatenated by 100.

thank u.

Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2) without making use of any floating point computations at all.

2 Answers   Mentor Graphics, Microsoft,

---

main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

2 Answers  

---

void main() { int c; c=printf("Hello world"); printf("\n%d",c); }

2 Answers  

---

main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

---

void main() { int i=5; printf("%d",i++ + ++i); }

3 Answers  

---

What is the difference between proc means and proc tabulate ? explain with a simple example when you have to use means or tabulate?

1 Answers  

---

write a c-program to display the time using FOR loop

3 Answers   HCL,

---

int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

---

PROG. TO PRODUCE 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1

1 Answers  

---

what is variable length argument list?

2 Answers  

---

what is the code of the output of print the 10 fibonacci number series

2 Answers  

---

#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

2 Answers   CNSI,

---