A Wheel accelerates from rest with an acceleration of 6
rad/sec seq. How many revolutions are experienced in 4 sec.?
give answer with solution.
Answers were Sorted based on User's Feedback
Answer / mechatronics89
a= 6 rad/sec^2
let Q denotes the degree ,in radians ,by which the wheel
rotates. Then we can say
Q= (1/2)*a*t^2 (since initial velocity is 0)
=.5*6*16
=48 radians..
no.of revolution = 48/2*pi = 24/pi
Is This Answer Correct ? | 8 Yes | 5 No |
Answer / babytesla
Angular distance covered = 0.5((6rad/sec^2 )(1rev./2πrad)(4sec)^2) = 7.64rev
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sanjay
s=u*t+(1/2)*a*t~2
s=0*4+(1/2)*6*16
s=48 Radians
One radian=180 Degree
2 radian= 360 Degree=one complete revolution
so, 24 Revolutions
Is This Answer Correct ? | 5 Yes | 6 No |
Answer / xxxxxx
axial velocity=radial velocity* no. of revolution*time
acc.=axial v/t(time)
6*4=revolution n
Is This Answer Correct ? | 0 Yes | 2 No |
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