Answer / soundararajan krishnan

I think the actual question may be like
sqrt(x+sqrt(x+sqrt(x+sqrt(x+...))))=2;
Find the value of x?

When we solve this the value of x is 2.

Let A = sqrt(x+sqrt(x+sqrt(x+sqrt(x+...)))) ------(1)
We can write this as,

A = sqrt (x+A) ------(2) using formula (1)

Since A = sqrt(x+sqrt(x+sqrt(x+sqrt(x+...)))) = 2,

we can write the equation (2) as,

2 = sqrt(x+2)

square this equation,

4 = x+2

Then x = 2.

Answer / karthik

the value of x=4;
start from the innermost sqrt
1.sqrt(4)=2;
2.sqrt(4+2)=sqrt(6)=2// since ans is (2 root 3)it will
consider only 2 and left root 3
3.sqrt(4+2)=sqrt(6)=2

in the last root (sqrt(4+2))= ans is 2 root(3) just elimnate
root(3)

thus the remaining ans is 2

there fore X=4////

Answer / chandan

Here x will be 2.028530
only then the exact value of
the given expression will be 2.
Because if we pass int value &
it will handle like float value
otherwise its o/p will be 0.So
here we have to use %f in the
printf statement to get actual
value of given expression.

Answer / rukmanee

the value of x=1

change to postfix a/(b+c*d-e)

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